Coordinate Geometry Quiz
Grade 10 · Math · Quiz
Challenge your skills with coordinate geometry problems involving lines, circles, and distances.
Questions
What is the equation of the line through (2, 3) with slope −½?
- y = −½x + 4
- y = −½x + 2
- y = −½x + 3
- y = ½x + 4
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Answer: y = −½x + 4
Using point-slope: y−3 = −½(x−2) → y = −½x + 1 + 3 = −½x + 4.
Find the radius of the circle x² + y² − 4x + 6y − 12 = 0.
- 5
- √12
- 4
- √25
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Answer: 5
Complete the square: (x−2)²+(y+3)²=4+9+12=25, so r=√25=5.
Which point lies on the circle (x−1)² + (y+2)² = 25?
- (4, 2)
- (1, −7)
- (−4, −2)
- (6, −2)
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Answer: (1, −7)
Check: (1−1)²+(−7+2)²=0+25=25. ✓
What is the slope of the perpendicular bisector of the segment joining (0, 0) and (4, 2)?
- −2
- ½
- 2
- −½
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Answer: −2
Slope of PQ = (2−0)/(4−0) = ½. Perpendicular slope = −1/(½) = −2.
The line y = 2x + 5 is parallel to y = 2x − 3.
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Answer: True
Both lines have slope 2; parallel lines have equal slopes and different y-intercepts.
Points A(0,0), B(4,0), and C(4,3) form a triangle. What is the length of AC?
- 5
- 4
- 3
- 7
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Answer: 5
AC = √[(4−0)²+(3−0)²] = √[16+9] = √25 = 5.
The midpoint of segment PQ is M(3, −1). If P = (1, 5), what are the coordinates of Q?
- (5, −7)
- (4, 2)
- (2, 4)
- (−1, 7)
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Answer: (5, −7)
Midpoint formula: (1+Qx)/2=3 → Qx=5; (5+Qy)/2=−1 → Qy=−7.
The general equation of a circle can be converted to standard form by ______ the square.
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Answer: completing
Completing the square on the x and y terms converts the general form to (x−h)²+(y−k)²=r².
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