Solutions and Mixtures Quiz
Grade 10 · Science · Quiz
Test your knowledge of solution chemistry, concentration calculations, solubility factors, and colligative properties.
Questions
How many moles of solute are present in 500 mL of a 3.0 M solution?
- 0.50 mol
- 1.50 mol
- 6.0 mol
- 3.0 mol
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Answer: 1.50 mol
moles = M × V = 3.0 mol/L × 0.500 L = 1.50 mol
A 200 mL sample of 4.0 M HCl is diluted to 800 mL. What is the new molarity?
- 16.0 M
- 2.0 M
- 0.5 M
- 1.0 M
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Answer: 1.0 M
M₁V₁ = M₂V₂: (4.0 M)(200 mL) = M₂(800 mL). M₂ = 800/800 = 1.0 M
Which of the following substances would make the best electrolyte when dissolved in water?
- Sugar (C₁₂H₂₂O₁₁)
- Ethanol (C₂H₅OH)
- Sodium chloride (NaCl)
- Vegetable oil
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Answer: Sodium chloride (NaCl)
NaCl dissociates into Na⁺ and Cl⁻ ions, allowing electrical conduction. Sugar and ethanol are nonelectrolytes; oil doesn't dissolve in water
The freezing point depression constant (Kf) of water is 1.86°C/m. What is the freezing point of a solution of 0.5 mol NaCl (i=2) in 1 kg of water?
- −0.93°C
- −1.86°C
- −3.72°C
- −0.465°C
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Answer: −1.86°C
ΔTf = Kf × m × i = 1.86 × 0.5 × 2 = 1.86°C. Freezing point = 0 - 1.86 = -1.86°C
Which solution has the highest boiling point?
- Pure water
- 0.5 m glucose solution
- 0.5 m NaCl solution (i=2)
- 0.5 m MgCl₂ solution (i=3)
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Answer: 0.5 m MgCl₂ solution (i=3)
ΔTb = Kb × m × i. MgCl₂ (i=3) gives highest particle count: 0.5×3=1.5 effective molality vs. NaCl 0.5×2=1.0 and glucose 0.5×1=0.5
A solute dissolves exothermically in water. What happens to its solubility when temperature increases?
- Solubility increases
- Solubility decreases
- Solubility stays the same
- Solubility increases then decreases
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Answer: Solubility decreases
For exothermic dissolution, higher temperature shifts equilibrium (Le Chatelier's principle) toward the dissolution being reversed, so solubility decreases
Osmotic pressure is a colligative property that can be used to determine the molar mass of large molecules like proteins.
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Answer: True
Osmotic pressure π = iMRT is measurable even for dilute solutions of large molecules, allowing molar mass determination: M = π/(iRT)
The formula M₁V₁ = M₂V₂ is used when ________ a concentrated solution to a lower concentration.
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Answer: diluting
The dilution formula M₁V₁ = M₂V₂ conserves moles of solute; used to calculate the new concentration or volume after adding solvent
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