Complex Numbers

Grade 11 · Math · Study Guide

Explore complex numbers of the form a + bi, learn arithmetic operations, and understand the complex plane.

A complex number has the form a + bi, where a is the real part, b is the imaginary part, and i = sqrt(-1). The set of complex numbers extends the reals to include solutions to equations like x^2 = -1.

You add/subtract complex numbers by combining real and imaginary parts separately. Multiply using FOIL and replace i^2 with -1. To divide, multiply numerator and denominator by the complex conjugate of the denominator.

The complex conjugate of a + bi is a - bi. The modulus is |a + bi| = sqrt(a^2 + b^2), which is the distance from the origin in the complex plane.

Powers of i (cycle of 4)
PowerValue
i^1i
i^2-1
i^3-i
i^41
i^5i (cycle repeats)
Complex Number Operations
OperationRule
Add(a+bi) + (c+di) = (a+c) + (b+d)i
Subtract(a+bi) - (c+di) = (a-c) + (b-d)i
Multiply(a+bi)(c+di) = (ac-bd) + (ad+bc)i
DivideMultiply numerator and denominator by conjugate of denominator

Key terms

Imaginary unit
i = sqrt(-1), so i^2 = -1.
Complex number
A number of the form a + bi where a and b are real numbers.
Complex conjugate
The conjugate of a + bi is a - bi; their product is a^2 + b^2.
Modulus
|a + bi| = sqrt(a^2 + b^2); the distance from the origin in the complex plane.

Practice questions

  1. What is i^2?

    1. 1
    2. i
    3. -1
    4. -i
    Show answer

    By definition, i = sqrt(-1), so i^2 = -1.

  2. Add: (3 + 4i) + (1 - 2i).

    Show answer

    Real parts: 3+1=4; imaginary parts: 4+(-2)=2. Result: 4 + 2i.

  3. What is (2 + 3i)(2 - 3i)?

    1. 4 + 9i
    2. 13
    3. 4 - 9
    4. -5
    Show answer

    (a+bi)(a-bi) = a^2 + b^2 = 4 + 9 = 13.

  4. Simplify i^7.

    Show answer

    Powers of i cycle with period 4. 7 mod 4 = 3, so i^7 = i^3 = -i.

  5. What is the modulus of 3 + 4i?

    1. 7
    2. sqrt(7)
    3. 5
    4. 25
    Show answer

    |3 + 4i| = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.

Fun facts

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