Exponential Growth and Decay Quiz
Grade 11 · Math · Quiz
10 questions on growth/decay models, half-life, doubling time, and compound interest.
Questions
Which value of b makes f(x) = 3*b^x an exponential growth function?
- b = 0.5
- b = 1
- b = 1.2
- b = 0
Show answer
Answer: b = 1.2
Growth requires b > 1. Only b = 1.2 satisfies this.
A car worth $20,000 depreciates 15% per year. What is it worth after 2 years?
- $14,450
- $17,000
- $16,000
- $15,000
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Answer: $14,450
f(2) = 20000(0.85)^2 = 20000 x 0.7225 = $14,450.
f(t) = 100e^(-0.02t). What is f(0)?
- 0
- -0.02
- 100
- e
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Answer: 100
f(0) = 100e^0 = 100 x 1 = 100.
A bacteria culture doubles every 3 hours. Starting from 50 bacteria, how many after 9 hours?
- 200
- 300
- 400
- 450
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Answer: 400
9 hours = 3 doubling periods. 50 x 2^3 = 50 x 8 = 400.
Continuous compound interest: A = Pe^(rt). Find A if P=1000, r=0.06, t=5.
- $1300.00
- $1349.86
- $1060.00
- $1416.18
Show answer
Answer: $1349.86
A = 1000 * e^(0.30) = 1000 x 1.34986 = $1349.86.
A substance has half-life of 20 days. After 60 days, what fraction remains?
- 1/4
- 1/8
- 1/6
- 1/3
Show answer
Answer: 1/8
60 / 20 = 3 half-lives. (1/2)^3 = 1/8.
What is the doubling time for continuous growth rate k = 0.1?
- 6.93 years
- 10 years
- 1 year
- 0.1 years
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Answer: 6.93 years
t_double = ln(2)/0.1 = 0.693/0.1 = 6.93 years.
The graph of f(x) = 2^x has a horizontal asymptote at:
- y = 1
- y = 2
- y = 0
- x = 0
Show answer
Answer: y = 0
As x -> -inf, 2^x -> 0 but never reaches it; the asymptote is y = 0.
Which equation models 10% annual growth from an initial value of 500?
- f(t) = 500(0.9)^t
- f(t) = 500(1.1)^t
- f(t) = 500 + 10t
- f(t) = 500e^t
Show answer
Answer: f(t) = 500(1.1)^t
Discrete growth: f(t) = a(1+r)^t = 500(1.10)^t.
Solve for t: 80 = 160e^(-0.04t). Round to nearest whole number.
- t = 17
- t = 10
- t = 25
- t = 20
Show answer
Answer: t = 17
0.5 = e^(-0.04t) -> ln(0.5) = -0.04t -> -0.693 = -0.04t -> t = 17.3, rounds to 17.
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