Trigonometric Functions Quiz
Grade 11 · Math · Quiz
10 questions covering trig ratios, radian conversion, the unit circle, and key identities.
Questions
What is tan(45 degrees)?
- sqrt(2)/2
- sqrt(3)
- 1
- 0
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Answer: 1
tan(45) = sin(45)/cos(45) = (sqrt(2)/2)/(sqrt(2)/2) = 1.
Convert 3*pi/4 radians to degrees.
- 120
- 135
- 150
- 270
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Answer: 135
(3*pi/4) * (180/pi) = 3*180/4 = 135 degrees.
On the unit circle, what is sin(pi)?
- 1
- -1
- 0
- pi
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Answer: 0
At theta = pi, the point is (-1, 0). y-coordinate = sin(pi) = 0.
What is the amplitude of y = 4*sin(x)?
- 1
- 2
- 4
- pi
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Answer: 4
Amplitude = |A| in y = A*sin(x). Here A = 4, amplitude = 4.
Simplify using a Pythagorean identity: 1 - cos^2(theta).
- sin^2(theta)
- tan^2(theta)
- sec^2(theta)
- cos(theta)
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Answer: sin^2(theta)
From sin^2 + cos^2 = 1: 1 - cos^2 = sin^2.
In which quadrant is sin(theta) < 0 and cos(theta) > 0?
- Quadrant I
- Quadrant II
- Quadrant III
- Quadrant IV
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Answer: Quadrant IV
Quadrant IV: x > 0 (cos > 0) and y < 0 (sin < 0).
What is cos(0)?
- 0
- 1
- -1
- undefined
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Answer: 1
At theta = 0, the unit circle point is (1, 0). cos(0) = 1.
The period of y = tan(x) is:
- 2*pi
- pi
- pi/2
- 4*pi
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Answer: pi
The tangent function repeats every pi radians.
Which identity equals 1 + tan^2(theta)?
- sin^2(theta)
- sec^2(theta)
- csc^2(theta)
- cos^2(theta)
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Answer: sec^2(theta)
Divide sin^2 + cos^2 = 1 by cos^2: tan^2 + 1 = sec^2.
What is sin(7*pi/6)?
- 1/2
- sqrt(3)/2
- -1/2
- -sqrt(3)/2
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Answer: -1/2
7*pi/6 = pi + pi/6 (Quadrant III). sin(pi + pi/6) = -sin(pi/6) = -1/2.
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