Kinematics Quiz
Grade 11 · Science · Quiz
10 questions testing mastery of kinematic equations, graph interpretation, and projectile motion.
Questions
What is the difference between distance and displacement?
- They are the same thing
- Distance is a vector; displacement is a scalar
- Displacement is the change in position (vector); distance is total path length (scalar)
- Distance is always larger than displacement
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Answer: Displacement is the change in position (vector); distance is total path length (scalar)
Displacement has direction and depends only on start/end points; distance is always positive and includes the entire path.
A car traveling at 20 m/s brakes to rest over 4.0 s. What is the acceleration?
- −5.0 m/s²
- +5.0 m/s²
- −80 m/s²
- +80 m/s²
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Answer: −5.0 m/s²
a = Δv/Δt = (0 − 20)/4.0 = −5.0 m/s². Negative indicates deceleration in the direction of motion.
A rock is dropped from a 45 m cliff. How long does it take to hit the ground? (g = 10 m/s²)
- 2.1 s
- 3.0 s
- 4.5 s
- 6.7 s
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Answer: 3.0 s
Δx = ½gt² → 45 = ½(10)t² → t² = 9 → t = 3.0 s.
On a position-time graph, a horizontal line indicates the object is:
- Accelerating
- Moving at constant velocity
- At rest
- Decelerating
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Answer: At rest
A horizontal line on an x-t graph has zero slope, meaning zero velocity — the object is stationary.
Using v² = v₀² + 2aΔx, what is the final velocity of an object starting at 5.0 m/s, accelerating at 2.0 m/s² over 10 m?
- 7.0 m/s
- 9.0 m/s
- 25 m/s
- 45 m/s
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Answer: 7.0 m/s
v² = v₀² + 2aΔx = 5² + 2(2.0)(10) = 25 + 40 = 65; v = √65 ≈ 8.1 m/s.
In projectile motion, the vertical acceleration is:
- 0 m/s²
- 9.8 m/s² upward
- 9.8 m/s² downward
- Depends on the launch angle
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Answer: 9.8 m/s² downward
Gravity provides a constant downward acceleration of 9.8 m/s² regardless of horizontal motion or launch angle.
At what launch angle does a projectile achieve maximum range?
- 30°
- 45°
- 60°
- 90°
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Answer: 45°
Range = (v₀²sin2θ)/g, maximized when sin2θ = 1, i.e., 2θ = 90°, θ = 45°.
The area under a velocity-time graph represents:
- Acceleration
- Displacement
- Speed
- Force
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Answer: Displacement
Area = v × t = displacement (for constant v). For varying v, the area under the v-t curve gives total displacement.
An object moving at 10 m/s experiences acceleration of −2 m/s². How long until it stops?
- 2 s
- 5 s
- 10 s
- 20 s
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Answer: 5 s
v = v₀ + at → 0 = 10 + (−2)t → t = 5 s.
A ball is thrown horizontally at 15 m/s from a 20 m high cliff. What is its horizontal range? (g = 10 m/s²)
- 10 m
- 20 m
- 30 m
- 45 m
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Answer: 30 m
Time to fall: 20 = ½(10)t² → t = 2 s. Range = 15 × 2 = 30 m.
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