Stoichiometry Quiz
Grade 11 · Science · Quiz
10 questions covering mole calculations, balanced equations, limiting reagents, and percent yield.
Questions
What does Avogadro's number represent?
- The number of protons in a mole
- 6.022 × 10²³ particles per mole
- The molar mass of any element
- The charge on one mole of electrons
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Answer: 6.022 × 10²³ particles per mole
Avogadro's number is the number of representative particles in exactly one mole of a substance.
Balance: _Fe + _O₂ → _Fe₂O₃. What are the coefficients?
- 1, 1, 1
- 2, 3, 2
- 4, 3, 2
- 3, 2, 2
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Answer: 4, 3, 2
4Fe + 3O₂ → 2Fe₂O₃ balances 4 Fe atoms and 6 O atoms on each side.
How many moles are in 36.04 g of water (molar mass 18.02 g/mol)?
- 0.5 mol
- 1.0 mol
- 2.0 mol
- 4.0 mol
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Answer: 2.0 mol
36.04 ÷ 18.02 = 2.0 mol.
In 2SO₂ + O₂ → 2SO₃, with 4 mol SO₂ and 1 mol O₂ available, which is limiting?
- SO₂
- O₂
- SO₃
- Neither
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Answer: O₂
4 mol SO₂ needs 2 mol O₂, but only 1 mol is available — O₂ is limiting.
What mass of CO₂ (44.01 g/mol) forms from complete combustion of 1 mol CH₄? (CH₄ + 2O₂ → CO₂ + 2H₂O)
- 16.05 g
- 28.01 g
- 44.01 g
- 88.02 g
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Answer: 44.01 g
1:1 mole ratio of CH₄ to CO₂ means 1 mol CH₄ → 1 mol CO₂ = 44.01 g.
Theoretical yield 8.0 g, actual yield 6.4 g. What is percent yield?
- 70%
- 75%
- 80%
- 85%
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Answer: 80%
(6.4 / 8.0) × 100 = 80%.
How many grams are in 3.0 mol of NaCl (molar mass 58.44 g/mol)?
- 19.48 g
- 58.44 g
- 116.88 g
- 175.32 g
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Answer: 175.32 g
3.0 mol × 58.44 g/mol = 175.32 g.
Which quantity is NOT needed for a mass-to-mass stoichiometric calculation?
- A balanced chemical equation
- Molar masses of reactants/products
- The temperature of the reaction
- The given mass of the starting material
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Answer: The temperature of the reaction
Temperature is not required for mass-to-mass stoichiometry — you need the equation, molar masses, and given mass.
At STP, what volume does 2.0 mol of ideal gas occupy?
- 11.2 L
- 22.4 L
- 33.6 L
- 44.8 L
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Answer: 44.8 L
At STP, 1 mol ideal gas = 22.4 L. So 2.0 mol × 22.4 = 44.8 L.
In 5A → 3B, how many moles of B form from 15.0 mol of A?
- 3.0 mol
- 5.0 mol
- 9.0 mol
- 25.0 mol
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Answer: 9.0 mol
15.0 mol A × (3 mol B / 5 mol A) = 9.0 mol B.
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