Thermodynamics Quiz
Grade 11 · Science · Quiz
Challenge your understanding of thermodynamic laws, processes, entropy, and heat engine efficiency.
Questions
A gas expands isothermally and does 500 J of work on its surroundings. How much heat is absorbed by the gas?
- 0 J
- 250 J
- 500 J
- 1000 J
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Answer: 500 J
For an isothermal process of an ideal gas, ΔU = 0. Therefore from ΔU = Q - W: Q = W = 500 J.
Which thermodynamic process is represented by a vertical line on a PV diagram?
- Isothermal
- Isobaric
- Isochoric
- Adiabatic
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Answer: Isochoric
A vertical line on a PV diagram means volume is constant — that is an isochoric process.
A heat engine absorbs 1000 J from a hot reservoir and rejects 400 J to a cold reservoir. What is its efficiency?
- 40%
- 60%
- 67%
- 250%
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Answer: 60%
Efficiency = W_out/Q_in = (Q_hot - Q_cold)/Q_hot = (1000 - 400)/1000 = 600/1000 = 60%.
What is the SI unit of entropy?
- Joules (J)
- Watts (W)
- Joules per Kelvin (J/K)
- Kelvin (K)
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Answer: Joules per Kelvin (J/K)
Entropy S has units of J/K (joules per kelvin), since ΔS = Q_rev/T.
Ice melting at 0°C is an example of which type of process?
- Adiabatic
- Isobaric phase change
- Isochoric
- Carnot cycle
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Answer: Isobaric phase change
Melting ice at constant atmospheric pressure is an isobaric phase change; heat is absorbed (latent heat) at constant temperature and pressure.
In a Carnot cycle, what is true about the two adiabatic processes?
- They involve heat exchange with reservoirs
- They occur at constant temperature
- No heat is exchanged during them
- They define the efficiency alone
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Answer: No heat is exchanged during them
The two adiabatic steps in a Carnot cycle involve no heat exchange (Q = 0); they connect the isothermal expansion and compression steps.
All reversible heat engines operating between the same two temperatures have the same efficiency.
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Answer: True
This is a consequence of the Second Law (Carnot's theorem): all reversible engines between the same temperatures achieve the Carnot efficiency; no engine can do better.
The equation Q = mcΔT is used to calculate the _____ heat absorbed or released by a substance.
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Answer: sensible
Q = mcΔT calculates sensible heat — heat that causes a temperature change. Latent heat (Q = mL) applies during phase changes at constant temperature.
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