Applications of Derivatives Quiz
Grade 12 · Math · Quiz
10 questions on critical points, concavity, inflection points, and optimization.
Questions
Where is f(x) = x² - 4x + 3 decreasing?
- x > 2
- x < 2
- x > 4
- x < 0
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Answer: x < 2
f′(x) = 2x - 4 < 0 when x < 2.
Find all critical points of f(x) = 2x³ - 6x.
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f′(x) = 6x² - 6 = 0 → x² = 1 → x = ±1.
If f′(x) changes from negative to positive at x = c, then x = c is a:
- Local maximum
- Inflection point
- Local minimum
- Critical point only
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Answer: Local minimum
First Derivative Test: f′ goes from − to + means the function was decreasing then increasing — a local minimum.
A function can have a local maximum at a point where f′ is undefined.
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For example, f(x) = -|x| has a local maximum at x = 0 where f′(0) is undefined.
For f(x) = x⁴, what does the Second Derivative Test tell us about x = 0?
- Local max
- Local min
- Inflection point
- Inconclusive
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Answer: Inconclusive
f″(x) = 12x². f″(0) = 0, so the Second Derivative Test is inconclusive. (It is actually a global minimum.)
Find the x-coordinate of the inflection point of f(x) = x³ - 3x².
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f″(x) = 6x - 6 = 0 → x = 1. Sign changes at x = 1, confirming inflection.
A box with no top has a square base of side x and height h. Volume = 32. To minimize surface area, what equation relates x and h?
- x² + 4xh = 32
- x²h = 32
- 2x² + 4xh = 32
- 4xh = 32
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Answer: x²h = 32
Volume constraint: V = x²h = 32.
Every local maximum is also a global maximum.
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A function can have multiple local maxima; the global maximum is the highest among all of them.
The graph of f is concave up on (1, 5) and concave down on (5, ∞). Where is the inflection point?
- x = 1
- x = 3
- x = 5
- x = ∞
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Answer: x = 5
Concavity changes at x = 5 — that is the inflection point.
What does it mean for f to be increasing on an interval?
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A positive first derivative means the function's output increases as x increases.
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