Differential Equations Intro

Grade 12 · Math · Study Guide

Understand what a differential equation is and how to solve separable first-order equations.

A differential equation (DE) is an equation involving a function and its derivatives, such as dy/dx = ky. A solution is a function y = f(x) that satisfies the equation. The general solution contains an arbitrary constant C; an initial condition determines the particular solution.

Separable equations are solved by algebraically separating variables: move all y-terms to one side and all x-terms to the other, then integrate both sides. For example, dy/dx = ky separates to dy/y = k dx, integrating to ln|y| = kx + C, giving y = Ae^(kx).

A slope field (direction field) is a graphical tool that shows the slope dy/dx at each point (x, y), giving a visual picture of all possible solution curves without solving the equation analytically.

Solving Separable DEs
StepAction
1Separate variables: g(y) dy = f(x) dx
2Integrate both sides
3Solve for y (general solution)
4Apply initial condition to find C
Common DE Models
ModelEquationSolution
Exponential growthdy/dt = ky, k > 0y = y₀ e^(kt)
Exponential decaydy/dt = ky, k < 0y = y₀ e^(kt)
Newton's coolingdT/dt = k(T - Tₑ)T = Tₑ + (T₀ - Tₑ)e^(kt)

Key terms

Differential equation
An equation relating a function to one or more of its derivatives.
Separable equation
A DE where variables can be separated: g(y)dy = f(x)dx.
General solution
The family of all solutions, including the arbitrary constant C.
Slope field
A plot of short line segments showing dy/dx at each (x, y) point.

Practice questions

  1. Which of the following is a differential equation?

    1. y = 3x + 2
    2. dy/dx = 2y
    3. ∫ y dx = x²
    4. y² + x = 5
    Show answer

    A differential equation relates a function to its derivative. dy/dx = 2y fits that definition.

  2. Solve the separable DE dy/dx = 3x², given y(0) = 1.

    Show answer

    dy = 3x² dx → y = x³ + C. y(0)=1: 1 = 0 + C → C = 1. So y = x³ + 1.

  3. The general solution to dy/dx = -2y is:

    1. y = Ce^(2x)
    2. y = Ce^(-2x)
    3. y = -2x + C
    4. y = Ce^x
    Show answer

    Separate: dy/y = -2 dx → ln|y| = -2x + C₀ → y = Ce^(-2x).

  4. An initial condition is needed to find the particular solution of a differential equation.

    Show answer

    The general solution has arbitrary constant C. An initial condition like y(0) = 5 pins down C to give the particular solution.

  5. A population grows according to dP/dt = 0.05P. If P(0) = 200, find P(t).

    Show answer

    Exponential growth model: P = P₀ e^(kt). P₀ = 200, k = 0.05. So P(t) = 200e^(0.05t).

Fun facts

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