Integration Basics
Grade 12 · Math · Study Guide
An introduction to antiderivatives, definite integrals, the Fundamental Theorem of Calculus, and core integration techniques.
Integration is the reverse process of differentiation. An antiderivative (or indefinite integral) of f(x) is any function F(x) such that F'(x) = f(x). We write ∫f(x)dx = F(x) + C, where C is the constant of integration.
The Power Rule for integration states ∫xⁿ dx = xⁿ⁺¹/(n+1) + C for n ≠ -1. Other key antiderivatives include ∫eˣ dx = eˣ + C, ∫(1/x) dx = ln|x| + C, ∫cos x dx = sin x + C, and ∫sin x dx = -cos x + C.
The Fundamental Theorem of Calculus (FTC) connects differentiation and integration. Part 1 states that if F(x) = ∫ₐˣ f(t) dt, then F'(x) = f(x). Part 2 states that ∫ₐᵇ f(x) dx = F(b) - F(a), allowing exact evaluation of definite integrals. The definite integral ∫ₐᵇ f(x) dx represents the net signed area between the curve and the x-axis from x=a to x=b.
U-substitution is the main technique for integrating composite functions, analogous to the Chain Rule in differentiation. Let u = g(x), then du = g'(x) dx, transforming the integral into a simpler form.
Key terms
- Antiderivative
- A function F(x) whose derivative is f(x); also called an indefinite integral
- Definite Integral
- ∫ₐᵇ f(x) dx; represents net signed area under f from a to b, evaluated as F(b) - F(a)
- Constant of Integration
- The +C added to every indefinite integral, representing the family of all antiderivatives
- Fundamental Theorem of Calculus
- Connects differentiation and integration; Part 2 states ∫ₐᵇ f(x)dx = F(b) - F(a)
- U-Substitution
- An integration technique where a substitution u = g(x) simplifies a composite integrand
- Net Signed Area
- The value of a definite integral; area above x-axis counts positive, area below counts negative
Flashcards
- ∫xⁿ dx
- xⁿ⁺¹/(n+1) + C, provided n ≠ -1
- ∫eˣ dx
- eˣ + C
- ∫cos x dx
- sin x + C
- ∫sin x dx
- -cos x + C
- ∫(1/x) dx
- ln|x| + C
- U-Substitution Steps
- 1) Choose u = g(x). 2) Compute du = g'(x)dx. 3) Rewrite integral in terms of u. 4) Integrate. 5) Substitute back.
- FTC Part 2
- ∫ₐᵇ f(x)dx = F(b) - F(a), where F is any antiderivative of f
- Area Between Curves
- ∫ₐᵇ [f(x) - g(x)] dx where f(x) ≥ g(x) on [a,b]
Questions
Evaluate ∫6x² dx.
- 2x³ + C
- 12x + C
- 3x² + C
- 6x³ + C
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Answer: 2x³ + C
Power Rule for integration: ∫6x² dx = 6 · x³/3 + C = 2x³ + C.
The Fundamental Theorem of Calculus Part 2 states that ∫ₐᵇ f(x)dx = F(b) ___ F(a).
Show answer
Answer: minus
FTC Part 2: ∫ₐᵇ f(x)dx = F(b) - F(a). You evaluate the antiderivative at the upper bound and subtract its value at the lower bound.
Using u-substitution, evaluate ∫2x(x² + 1)³ dx.
- (x² + 1)⁴ / 2 + C
- (x² + 1)⁴ / 4 + C
- x²(x² + 1)⁴ + C
- 8x²(x² + 1)² + C
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Answer: (x² + 1)⁴ / 4 + C
Let u = x²+1, du = 2x dx. Integral becomes ∫u³ du = u⁴/4 + C = (x²+1)⁴/4 + C.
The definite integral ∫₀¹ x² dx equals 1/3.
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Answer: True
∫₀¹ x² dx = [x³/3]₀¹ = 1/3 - 0 = 1/3.
What is ∫(1/x) dx?
- x⁻² + C
- -x⁻² + C
- ln|x| + C
- 1 + C
Show answer
Answer: ln|x| + C
∫(1/x) dx = ln|x| + C. The Power Rule fails for n = -1; this integral gives a logarithm.
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