L'Hopital's Rule Quiz
Grade 12 · Math · Quiz
10 questions on identifying indeterminate forms and applying L'Hopital's Rule.
Questions
What indeterminate form does lim(x→1) (x² - 1)/(x - 1) produce before applying L'Hopital?
- 1/0
- 0/0
- ∞/∞
- 0·∞
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Answer: 0/0
Substituting x=1: (1-1)/(1-1) = 0/0.
Evaluate lim(x→0) tan(x)/x.
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0/0 form. L'Hopital: lim sec²(x)/1 = sec²(0) = 1.
Evaluate lim(x→∞) ln(x)/x.
- 0
- 1
- ∞
- e
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Answer: 0
∞/∞ form. L'Hopital: lim (1/x)/1 = 0.
L'Hopital's Rule requires differentiating f/g using the quotient rule.
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You differentiate f and g separately (f′ and g′), then form f′/g′. Do NOT use the quotient rule.
Evaluate lim(x→0) (sin 3x)/(sin 2x).
- 1
- 3/2
- 2/3
- 0
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Answer: 3/2
0/0 form. L'Hopital: lim 3cos(3x)/(2cos(2x)) = 3(1)/(2(1)) = 3/2.
Evaluate lim(x→∞) x²/eˣ.
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Apply L'Hopital twice: lim x²/eˣ → lim 2x/eˣ → lim 2/eˣ = 0.
Which form does lim(x→0⁺) x·ln(x) produce?
- 0/0
- ∞/∞
- 0·∞
- 1^∞
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Answer: 0·∞
x→0⁺ gives x→0 and ln(x)→-∞, so the product is 0·(-∞), a 0·∞ form.
Evaluate lim(x→0⁺) x·ln(x).
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Rewrite as ln(x)/(1/x) — ∞/∞ form. L'Hopital: (1/x)/(-1/x²) = -x → 0.
If L'Hopital's Rule is applied and the new limit is still indeterminate, you can apply it again.
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L'Hopital's Rule can be applied repeatedly as long as the form remains 0/0 or ∞/∞.
Evaluate lim(x→∞) (3x² + 1)/(x² - 2) using L'Hopital's Rule.
- 0
- 3
- 1
- ∞
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Answer: 3
∞/∞ form. L'Hopital: lim 6x/(2x) = 3. (Or by dominant terms: 3x²/x² = 3.)
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