Divisibility Rules and Factors Quiz

Grade 6 · Math · Quiz

Test your knowledge of divisibility rules and how to find factors.

Questions

  1. Is 784 divisible by 2?

    1. Yes, it ends in an even digit
    2. No, it ends in an odd digit
    3. Yes, because it's greater than 2
    4. No, because 7+8+4=19
    Show answer

    Answer: Yes, it ends in an even digit

    784 ends in 4, which is even. Any number ending in 0, 2, 4, 6, or 8 is divisible by 2.

  2. 432 is divisible by 9.

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    Answer: True

    Digit sum: 4+3+2=9, and 9÷9=1 with no remainder. So 432 is divisible by 9.

  3. Which number is divisible by 5 but NOT by 10?

    1. 275
    2. 350
    3. 420
    4. 900
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    Answer: 275

    275 ends in 5 (divisible by 5) but not 0 (not divisible by 10). 350, 420, 900 all end in 0.

  4. The factors of 12 are 1, 2, 3, 4, 6, and ___.

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    Answer: 12

    Factors come in pairs: 1×12, 2×6, 3×4. All six factors of 12 are: 1, 2, 3, 4, 6, 12.

  5. Which number is divisible by 6?

    1. 114
    2. 112
    3. 115
    4. 116
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    Answer: 114

    Divisible by 2: 114 ends in 4 ✓. Divisible by 3: 1+1+4=6, and 6÷3=2 ✓. So 114 is divisible by 6.

  6. All odd numbers are divisible by 3.

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    Answer: False

    Only odd numbers whose digit sum is divisible by 3 are divisible by 3. Example: 11 is odd but NOT divisible by 3 (1+1=2).

  7. What is the sum of digits of 261, and is it divisible by 3?

    1. 9, yes
    2. 9, no
    3. 18, yes
    4. 8, no
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    Answer: 9, yes

    2+6+1=9. And 9 is divisible by 3 (9÷3=3). So 261 is divisible by 3.

  8. A number is divisible by 10 if its last digit is ___.

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    Answer: 0

    The rule for 10: the number must end in 0. This is because 10 = 2×5, and only numbers ending in 0 are divisible by both.

  9. How many factors does 36 have?

    1. 9
    2. 6
    3. 4
    4. 36
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    Answer: 9

    Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36. That's 9 factors. Pairs: 1×36, 2×18, 3×12, 4×9, 6×6.

  10. A number is divisible by 6 if it is divisible by:

    1. Both 2 and 3
    2. Both 3 and 5
    3. Both 2 and 4
    4. Both 2 and 9
    Show answer

    Answer: Both 2 and 3

    6 = 2 × 3, so any number divisible by 6 must be divisible by both of its prime factors: 2 and 3.

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