Inequalities and Absolute Value Equations Quiz
Grade 9 · Math · Quiz
Test your mastery of solving and interpreting inequalities, compound inequalities, and absolute value problems.
Questions
Solve: 4x − 3 ≤ 13
- x ≤ 4
- x ≥ 4
- x ≤ 2.5
- x ≥ −4
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Answer: x ≤ 4
4x − 3 ≤ 13 → 4x ≤ 16 → x ≤ 4.
Solve: −6 < 2x + 4 ≤ 10
- −5 < x ≤ 3
- −1 < x ≤ 7
- −5 ≤ x < 3
- −1 ≤ x < 7
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Answer: −5 < x ≤ 3
Subtract 4: −10 < 2x ≤ 6. Divide by 2: −5 < x ≤ 3.
Solve |x − 3| = 10.
- x = 7 or x = −7
- x = 13 or x = −7
- x = 7 or x = −13
- x = 13 only
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Answer: x = 13 or x = −7
x − 3 = 10 → x = 13, or x − 3 = −10 → x = −7.
Solve |4x − 8| ≤ 12.
- −1 ≤ x ≤ 5
- x ≤ −1 or x ≥ 5
- −5 ≤ x ≤ 1
- x ≤ −5 or x ≥ 1
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Answer: −1 ≤ x ≤ 5
|4x − 8| ≤ 12 means −12 ≤ 4x − 8 ≤ 12. Add 8: −4 ≤ 4x ≤ 20. Divide by 4: −1 ≤ x ≤ 5.
Which inequality has no solution?
- |x + 5| = 0
- |x − 2| > −1
- |x + 3| < −4
- 2|x| > 0
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Answer: |x + 3| < −4
|x + 3| < −4 has no solution because absolute value is always ≥ 0 and can never be less than a negative number.
Solve: −2(x + 3) > 4x − 6
- x > 0
- x < 0
- x > −6
- x < −6
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Answer: x < 0
Expand: −2x − 6 > 4x − 6. Add 2x: −6 > 6x − 6. Add 6: 0 > 6x. Divide by 6: x < 0.
The absolute value equation |2x + 6| = 0 has exactly one solution.
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Answer: True
|2x + 6| = 0 means 2x + 6 = 0, so x = −3. There is exactly one solution.
Solve |x| > 8. Write the solution as x < −8 or x > __.
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Answer: 8
|x| > 8 splits into x > 8 or x < −8 because any number more than 8 units from zero satisfies the condition.
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